CN1309433C - Method for distinguishing agricultural products or food with radiation treatment or not - Google Patents
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Abstract
本发明公开了一种区分辐照和未辐照农产品及食品的方法。该方法包括以下步骤:1)用盐酸除去待测样品中的碳酸盐,用H2O2除去待测样品中的有机物,制得颗粒直径为3-8μm的除去碳酸盐和有机物的矿物质;2)测量所述除去碳酸盐和有机物的矿物质的热释光发光曲线的峰面积积分值,以G1表示,然后将该矿物质经1kGy的辐照剂量辐照后,再测量其热释光发光曲线的峰面积积分值,以G2表示;如G1与G2的比值大于等于0.10,则该待测样品为被辐照过的农产品或食品,如G1与G2的比值小于0.10,则该待测样品为未被辐照过的农产品或食品。本发明的方法具有灵敏度高,样品制备简单,检测周期短,且不需用参照物,准确率高等优点。The invention discloses a method for distinguishing irradiated and non-irradiated agricultural products and food. The method comprises the steps of: 1) removing carbonate in the sample to be tested with hydrochloric acid, and removing organic matter in the sample to be tested with H 2 O 2 to obtain a mineral having a particle diameter of 3-8 μm for removing carbonate and organic matter. substance; 2) measure the peak area integral value of the thermoluminescence luminescence curve of the mineral matter that removes carbonate and organic matter, expressed in G1 , and then measure the mineral matter after being irradiated by an irradiation dose of 1kGy The peak area integral value of the thermoluminescent luminescence curve is represented by G2 ; if the ratio of G1 to G2 is greater than or equal to 0.10, the sample to be tested is an irradiated agricultural product or food, such as G1 and G2 The ratio of is less than 0.10, then the sample to be tested is an agricultural product or food that has not been irradiated. The method of the invention has the advantages of high sensitivity, simple sample preparation, short detection period, no need for reference objects, high accuracy and the like.
Description
技术领域technical field
本发明涉及一种区分辐照和未辐照农产品及食品的方法,特别涉及一种用热释光分析方法区分辐照和未辐照农产品及食品的方法。The invention relates to a method for distinguishing irradiated and non-irradiated agricultural products and food, in particular to a method for distinguishing irradiated and non-irradiated agricultural products and food by thermoluminescent analysis method.
背景技术Background technique
食品辐照是第二次世界大战后崛起的一种新型食品保藏技术,距今已有半个多世纪的历史。它是将电离辐射对物质作用的物理、化学和生物效应用于食品贮藏,达到杀虫、杀菌、抑制发芽、延缓成熟、检疫控制寄生虫感染和提高卫生质量的目的。由于食品辐照具有节能、效率高、不升温、安全可靠和保持食品良好感官品质等优点,又是对传统食品加工技术的补充和完善,在当前的食品加工和保藏领域中显现出极其广阔的前景。随着国际贸易全球化和辐照食品商业化的迅猛发展,越来越多的国家和组织对食品是否经过辐照的关注程度日益增加(Grolichova M,Dvorak P,MusilovaH.Employing Ionizing Radiation to Enhance Food Safety-a Review.Acta Vet.Brno,2004,73:143-149;Lutter R.Food Irradiation--The Neglected Solutionto Food-Borne Illness.Science,1999,286:2275-2281;陈其勋.中国食品辐照进展,北京:原子能出版社,1998:1-21)。因此,辐照食品检测方法的研究也势在必行。这不仅仅是消费者知情权的需要,还是消除国际贸易技术壁垒和促进辐照食品商业化的需要。Food irradiation is a new type of food preservation technology that emerged after the Second World War, and it has a history of more than half a century. It uses the physical, chemical and biological effects of ionizing radiation on substances in food storage to achieve the purpose of killing insects, sterilizing bacteria, inhibiting germination, delaying ripening, quarantine control of parasite infection and improving hygiene quality. Since food irradiation has the advantages of energy saving, high efficiency, no temperature rise, safety and reliability, and good sensory quality of food, it is also a supplement and improvement to traditional food processing technology, and it shows an extremely broad prospect in the current food processing and preservation field. prospect. With the rapid development of international trade globalization and irradiated food commercialization, more and more countries and organizations pay more and more attention to whether food has been irradiated (Grolichova M, Dvorak P, Musilova H. Employing Ionizing Radiation to Enhance Food Safety-a Review. Acta Vet. Brno, 2004, 73: 143-149; Lutter R. Food Irradiation--The Neglected Solution to Food-Borne Illness. Science, 1999, 286: 2275-2281; Chen Qixun. Progress in food irradiation in China , Beijing: Atomic Energy Press, 1998: 1-21). Therefore, the research on the detection method of irradiated food is also imperative. This is not only the need for consumers' right to know, but also the need to eliminate technical barriers to international trade and promote the commercialization of irradiated food.
在国际原子能机构支持和组织下对辐照食品检测技术进行了较广泛的研究。目前可用于检测辐照食品的方法主要有:电子自旋共振法,高效液相色谱法,气-质联机法,热释光发光法,激光成像检测法,DNA裂解产物检测法等九种方法(J Raffi,M Kent.Method of identification of irradiated foodstuffs,in:L.Nollet(Ed.).Handbook of Food Analysis,Marcel Dekker.New York,1996:1889-1906)。这些方法大都是根据辐照导致食品中的物理、化学、生物学和生理学变化而进行的。尤其自上世纪80年代末Sanderson发现食品中的矿物质实际上是热释光的来源,由于所有暴露于土壤或风沙中的食品都含有矿物残存,从理论上讲,几乎所有农产品都可用热释光分析法检测,这种方法的优越性和广泛适用性更凸显出来,而且此技术还具有无需参照物、辐照专一和灵敏度高的特点。但是随着人民生活水平和企业加工能力的提高,调味料产品的矿物污染源越来越少,现有的提取工艺难以满足热释光分析的需要。Under the support and organization of the International Atomic Energy Agency, extensive research has been carried out on the detection technology of irradiated food. At present, there are nine methods that can be used to detect irradiated food: electron spin resonance method, high performance liquid chromatography, gas-mass coupling method, thermoluminescence luminescence method, laser imaging detection method, and DNA cleavage product detection method. (J Raffi, M Kent. Method of identification of irradiated foodstuffs, in: L. Nollet (Ed.). Handbook of Food Analysis, Marcel Dekker. New York, 1996: 1889-1906). Most of these methods are based on the physical, chemical, biological and physiological changes in food caused by irradiation. Especially since the late 1980s, Sanderson discovered that the minerals in food are actually the source of thermoluminescence. Since all foods exposed to soil or sandstorms contain mineral residues, theoretically, almost all agricultural products can be thermoluminescent. The superiority and wide applicability of this method are more prominent, and this technology also has the characteristics of no reference object, specific irradiation and high sensitivity. However, with the improvement of people's living standards and the processing capacity of enterprises, the mineral pollution sources of seasoning products are becoming less and less, and the existing extraction technology is difficult to meet the needs of thermoluminescence analysis.
利用热释光分析法区分辐照和未辐照食品及农产品,首先就需要提取矿物质。提取的矿物质中夹杂的有机物和碳酸盐等杂质会使热释发光曲线出现“毛刺”峰,导致积分值偏大;加上碳酸盐晶体在低剂量和高剂量两个范围内的响应度不同,也会给试验结果带来较大误差。因此,除去实验材料中有机物和碳酸盐是提取矿物质的关键步骤,对试验结果有着较大的影响。Differentiation of irradiated and non-irradiated food and agricultural products using thermoluminescence analysis begins with the extraction of minerals. Impurities such as organic matter and carbonates included in the extracted minerals will cause "burr" peaks in the thermoluminescence curve, resulting in a larger integral value; plus the response of carbonate crystals in the low-dose and high-dose ranges Different degrees will also bring large errors to the test results. Therefore, the removal of organic matter and carbonate in the experimental materials is a key step in the extraction of minerals, which has a greater impact on the test results.
发明内容Contents of the invention
本发明的目的是提供一种区分辐照和未辐照农产品及食品的方法。The object of the present invention is to provide a method for distinguishing between irradiated and non-irradiated agricultural products and foods.
本发明所提供的区分辐照和未辐照农产品及食品的方法,包括以下步骤:The method for distinguishing irradiated and non-irradiated agricultural products and food provided by the present invention comprises the following steps:
1)用盐酸除去待测样品中的碳酸盐,用H2O2除去待测样品中的有机物,得到除去碳酸盐和有机物的矿物质;1) remove the carbonate in the sample to be tested with hydrochloric acid, use H 2 O 2 to remove the organic matter in the sample to be tested, obtain the mineral matter that removes the carbonate and the organic matter;
2)测量所述除去碳酸盐和有机物的矿物质的热释光发光曲线的峰面积积分值,以G1表示,然后将该矿物质经1kGy的辐照剂量辐照后,再测量其热释光发光曲线的峰面积积分值,以G2表示;如G1与G2的比值大于等于0.10,则该待测样品为被辐照过的农产品或食品,如G1与G2的比值小于0.10,则该待测样品为未被辐照过的农产品或食品。2) Measure the peak area integral value of the thermoluminescent luminescence curve of the mineral matter that has removed carbonate and organic matter, expressed as G1 , and then measure the thermal energy of the mineral matter after being irradiated with an irradiation dose of 1kGy. The peak area integral value of the luminescence and luminescence curve, expressed in G2 ; if the ratio of G1 to G2 is greater than or equal to 0.10, the sample to be tested is an irradiated agricultural product or food, such as the ratio of G1 to G2 If it is less than 0.10, the sample to be tested is an agricultural product or food that has not been irradiated.
农产品的待测样品可取自农产品的表面润洗物,还可取自农产品的任何部位。The samples to be tested of the agricultural products can be taken from the surface rinse of the agricultural products, and can also be taken from any part of the agricultural products.
食品的待测样品可取自食品的任何部分。The food sample to be tested can be taken from any part of the food.
除去碳酸盐和有机物的矿物质的颗粒大小会直接影响剂量吸收的不均匀性,过小的颗粒具有很强的表面效应,使热释光信号过强,过大的颗粒表面效应过小,使热释光信号过弱。为了得到强度适宜的热释光信号,所述方法中,还包括在得到步骤1)中除去碳酸盐和有机物的矿物质之后,和所述步骤2)之前,对步骤1)中得到的除去碳酸盐和有机物的矿物质进行如下浮选的步骤:用去离子水悬浮步骤1)中得到的除去碳酸盐和有机物的矿物质,静置5-10分钟后,除去沉淀,将上层液静置1-2小时后,除去上层液,得到的沉淀是颗粒直径为3-8μm的除去碳酸盐和有机物的矿物质。The particle size of minerals that remove carbonates and organics will directly affect the inhomogeneity of dose absorption. Too small particles have a strong surface effect, which makes the thermoluminescent signal too strong. Too large particles have too little surface effect, Make the thermoluminescent signal too weak. In order to obtain a thermoluminescent signal with suitable intensity, the method also includes removing the mineral matter obtained in step 1) after obtaining the minerals in step 1) and before the step 2). The mineral matter of carbonate and organic matter carries out the step of flotation as follows: the mineral matter of removing carbonate and organic matter obtained in deionized water suspension step 1), after standing for 5-10 minutes, removes the precipitate, and the supernatant After standing still for 1-2 hours, the supernatant liquid is removed, and the precipitate obtained is minerals with a particle diameter of 3-8 μm and the removal of carbonate and organic matter.
所述盐酸为普通化学试剂,重量百分比浓度为36%。Said hydrochloric acid is a common chemical reagent, and its weight percentage concentration is 36%.
所述H2O2为普通化学试剂,重量百分比浓度为30%。The H 2 O 2 is a common chemical reagent with a concentration of 30% by weight.
所述热释光发光曲线的峰面积积分值为150℃-260℃区间的峰面积积分值。The peak area integral value of the thermoluminescence luminescence curve is the peak area integral value in the range of 150°C-260°C.
所述热释光发光曲线的测量参数为:S·A=4.56,D=2,F=2;升温速度每秒15℃;第1停留时间8s,温度保持在135℃;第2停留时间12s,温度保持在350℃。The measurement parameters of the thermoluminescent luminescence curve are: S·A=4.56, D=2, F=2; the heating rate is 15°C per second; the first residence time is 8s, and the temperature is maintained at 135°C; the second residence time is 12s , the temperature was maintained at 350°C.
本发明用直接酸化与氧化结合用水直接润洗表面法,除去待测样品中的碳酸盐和有机物,除去了影响峰面积积分值的有机物和碳酸盐,使试验结果的误差大大减小,并且不采用昂贵的钨酸钠溶液处理,降低了成本;本发明通过浮选获得颗粒直径为3-8μm均匀纯净的除去碳酸盐和有机物的矿物质,使热释光信号的强度适宜,使得试验重复性强,结果精确。本发明的方法具有灵敏度高,样品制备简单,检测周期短,且不需用参照物,准确率高等优点。本发明的方法可以用来检测能分离出矿物质的食品是否经过辐照处理,特别是对农产品尤为适用。The present invention combines direct acidification and oxidation with water to directly rinse the surface method to remove carbonates and organics in the sample to be tested, remove organics and carbonates that affect the integral value of the peak area, and greatly reduce the error of the test results. And it does not use expensive sodium tungstate solution to reduce the cost; the invention obtains uniform and pure minerals with a particle diameter of 3-8 μm and removes carbonate and organic matter through flotation, so that the intensity of the thermoluminescence signal is appropriate, making The test repeatability is strong and the result is accurate. The method of the invention has the advantages of high sensitivity, simple sample preparation, short detection period, no need for reference objects, high accuracy and the like. The method of the invention can be used to detect whether the food from which minerals can be separated has been irradiated, and is especially suitable for agricultural products.
附图说明Description of drawings
图1为85个样品的G1/G2统计图。Fig. 1 is the G 1 /G 2 statistical diagram of 85 samples.
图2为未经辐照中辣片的热释光第一发光曲线G1。Fig. 2 is the first thermoluminescence luminescence curve G 1 of unirradiated Chinese hot pepper.
图3为未经辐照中辣片的热释光第二发光曲线G2。Fig. 3 is the second thermoluminescent luminescence curve G 2 of unirradiated Chinese hot pepper flakes.
图4为经辐照土豆的热释光第一发光曲线G1。Fig. 4 is the thermoluminescence first luminescence curve G 1 of irradiated potatoes.
图5为经辐照土豆的热释光第二发光曲线G2。Fig. 5 is the second thermoluminescence luminescence curve G 2 of irradiated potatoes.
具体实施方式Detailed ways
以下实施例所述的方法,如无特殊说明均为常规方法。The methods described in the following examples are conventional methods unless otherwise specified.
实施例1、区分辐照食品和未辐照食品的方法Embodiment 1, the method for distinguishing irradiated food and non-irradiated food
一、分离提取矿物质1. Separation and extraction of minerals
RGD-3热释光分析仪(中国人民解放军防化研究院);KQ-100超声波发生器(昆山市超声仪器有限公司);LD4-2低速离心机(北京医用离心机厂);SG-202电热干燥箱(上海申光仪器仪表有限公司)。实验所用试剂均为分析纯。RGD-3 thermoluminescence analyzer (Chinese People's Liberation Army Chemical Defense Research Institute); KQ-100 ultrasonic generator (Kunshan Ultrasonic Instrument Co., Ltd.); LD4-2 low-speed centrifuge (Beijing Medical Centrifuge Factory); SG-202 Electric drying oven (Shanghai Shenguang Instrument Co., Ltd.). All reagents used in the experiment were of analytical grade.
将土豆(自由市场购买)分为两部分,其中一部分(1)不经辐照,另一部分(2)经0.1kGy辐照;中辣片(美全食品有限公司)不经辐照;海鲜上汤(百芬食品有限公司)经10kGy辐照;大麦苗粉(衡水麦苗粉厂)经6kGy辐照;花粉(中国农科院蜜蜂研究所)经4kGy辐照。Potatoes (purchased in the free market) were divided into two parts, one part (1) was not irradiated, and the other part (2) was irradiated at 0.1 kGy; Chinese spicy slices (Meiquan Food Co., Ltd.) were not irradiated; Soup (Baifen Food Co., Ltd.) was irradiated by 10kGy; barley grass powder (Hengshui Barley Flour Factory) was irradiated by 6kGy; pollen (Honey Bee Research Institute, Chinese Academy of Agricultural Sciences) was irradiated by 4kGy.
1、带有大量矿物土农产品-土豆样品的矿物质分离与提取:用水润洗土豆样品表面,将洗液收集在烧杯中,静置24小时后,缓慢倾出上清液,连烧杯和沉淀一起放入50-60℃烘箱内烘干。然后,将干燥后的沉淀样品放入研钵内轻轻研磨(防止局部温度过高),过200目筛,筛下的样品倒入烧杯。由于矿物样品成分复杂,其中有机物和碳酸盐对热释光信号影响较大,必须以酸化和氧化的方法除去。将上述过200目筛筛下的样品酸化与氧化,过程如下:向盛有10g土样的烧杯中加入10ml去离子水和10ml 36%的盐酸(过量),搅拌10min后加入20ml 30% H2O2(过量)静置反应24小时,然后加去离子水至满杯,每隔4小时倾出上层清液再加入去离子水,如此反复4-5次,至上清液pH=7。由于试验采用细粒法测热释光,细粒的大小会直接影响剂量吸收的不均匀性,过小的细粒具有很强的表面效应,使热释光信号过强。根据斯托克斯定律,浮选细粒直径为3-8um。所以进行浮选,浮选过程为:把经过酸化和氧化去除有机物和碳酸盐的土样,加去离子水至满杯,摇匀,静置10min,大于8um的颗粒已沉淀到杯底,将上层液倾入另一烧杯,再静置1小时。然后倾出上层液,烧杯底部的沉淀物即是直径为3-8um的细粒。最后用丙酮(分析纯)转移到小烧杯中,静置沉淀,弃去丙酮液,将沉淀下来的矿物质连同小烧杯放入50-60℃烘箱内烘干,称取5mg放入样品管,待热释光测量。1. Mineral separation and extraction of agricultural products with a large amount of mineral soil-potato samples: wash the surface of the potato samples with water, collect the washing liquid in a beaker, and after standing for 24 hours, slowly pour out the supernatant, connect the beaker and the sediment Put them together in a 50-60°C oven for drying. Then, put the dried precipitated sample into a mortar and grind it gently (to prevent the local temperature from being too high), pass through a 200-mesh sieve, and pour the sample under the sieve into a beaker. Due to the complex composition of mineral samples, organic matter and carbonates have a great influence on the thermoluminescence signal, and must be removed by acidification and oxidation. Acidify and oxidize the above-mentioned sample passed through a 200-mesh sieve, and the process is as follows: add 10 ml of deionized water and 10 ml of 36% hydrochloric acid (excessive) to a beaker containing 10 g of the soil sample, stir for 10 min, then add 20 ml of 30% H 2 O 2 (excessive) was left to react for 24 hours, then filled with deionized water to fill the cup, poured out the supernatant and added deionized water every 4 hours, and repeated this 4-5 times until the pH of the supernatant was 7. Since the test uses the fine particle method to measure the thermoluminescence, the size of the fine particles will directly affect the unevenness of dose absorption, and the fine particles that are too small have a strong surface effect, which makes the thermoluminescent signal too strong. According to Stokes law, the flotation fine particle diameter is 3-8um. Therefore, flotation is carried out. The flotation process is: add deionized water to the soil sample that has been acidified and oxidized to remove organic matter and carbonate to fill the cup, shake it well, and let it stand for 10 minutes. The particles larger than 8um have settled to the bottom of the cup. Pour the supernatant into another beaker and let it stand for 1 hour. Then pour out the supernatant, and the sediment at the bottom of the beaker is fine particles with a diameter of 3-8um. Finally, transfer it to a small beaker with acetone (analytically pure), let it stand for precipitation, discard the acetone solution, put the precipitated minerals together with the small beaker in an oven at 50-60°C for drying, weigh 5 mg and put it into the sample tube. To be measured by thermoluminescence.
2、香辛料、脱水蔬菜样品的矿物质分离与提取:分别取100g中辣片,海鲜上汤,大麦苗粉,花粉样品,按照如下方法直接酸化与氧化:加50ml 36%的盐酸(过量),搅拌10min后加入100ml 30%H2O2(过量),并用30KHz超声波处理,之后静置沉淀4小时,弃去上层有机物后离心,弃去上清液,收集沉淀物。将沉淀物用步骤1浮选的方法进行浮选。得到5mg矿物质样品,待热释光分析测量。2. Mineral separation and extraction of spices and dehydrated vegetable samples: take 100g of spicy slices, seafood soup, barley grass powder, and pollen samples, and directly acidify and oxidize them according to the following method: add 50ml of 36% hydrochloric acid (excessive), After stirring for 10 minutes, add 100ml of 30% H 2 O 2 (excessive amount), and use 30KHz ultrasonic treatment, then let it settle for 4 hours, discard the organic matter in the upper layer and centrifuge, discard the supernatant, and collect the precipitate. Flotate the sediment by the method of step 1 flotation. A 5 mg mineral sample was obtained, to be measured by thermoluminescence analysis.
二、热释光发光曲线测量2. Thermoluminescence Luminescence Curve Measurement
将步骤一得到的样品矿物质提取物分别均匀倒入热释光的测量小盘中,开启RGD-3热释光分析仪。仪器测量参数选取为:S·A=4.56,D=2,F=2;升温速度每秒15℃;第1停留时间8s,温度保持在135℃;第2停留时间12s,温度保持在350℃。发光峰取150℃-260℃区间的峰面积积分值。测量得到的发光曲线为第一发光曲线,用G1表示峰面积积分值。再将该测量过G1的样品全部收集到样品管中进行辐照,辐照装置采用中国农业科学院原子能利用研究所60Coγ辐照源,剂量为1kGy,剂量计采用重铬酸银剂量计。然后在同样条件下再进行第二次热释光测量,得到的发光曲线为第二发光曲线,用G2表示该峰面积积分值。样品的热释光分析数据如表1所示:Pour the sample mineral extract obtained in step 1 into the thermoluminescence measuring small dish evenly, and turn on the RGD-3 thermoluminescence analyzer. The measurement parameters of the instrument are selected as: S·A=4.56, D=2, F=2; the heating rate is 15°C per second; the first residence time is 8s, and the temperature is maintained at 135°C; the second residence time is 12s, and the temperature is maintained at 350°C . The luminescence peak takes the peak area integral value in the range of 150°C-260°C. The measured luminescence curve is the first luminescence curve, and G 1 is used to represent the integrated value of the peak area. Then all the samples that had measured G1 were collected into the sample tube for irradiation. The irradiation device used the Institute of Atomic Energy Utilization, Chinese Academy of Agricultural Sciences 60 Coγ irradiation source, the dose was 1kGy, and the dosimeter was a silver dichromate dosimeter. Then, the second thermoluminescence measurement is carried out under the same conditions, and the obtained luminescence curve is the second luminescence curve, and the integrated value of the peak area is represented by G2 . The thermoluminescent analysis data of the sample are shown in Table 1:
表1不同待测样品的热释光分析数据表
结果表明:辐照样品与未辐照样品相比较,发光曲线的峰面积积分值比值(G1/G2)的数据差异是明显的,其中未辐照的两个样品的G1/G2都远远小于0.10,而辐照的4个样品的G1/G2都大于0.10。参照国内外食品辐照的采用实际剂量,同时根据测量仪器本身检测的精准度,设定凡是辐照剂量在0.10kGy以上(包括0.10kGy)的食品,认定为辐照过的食品;如果食品本身或者其中有某种辅料接受辐照剂量小于0.10kGy,则认定食品没有接受辐照。所以,当样品中提取的矿物质接受辐照剂量1kGy后,其发光曲线的峰面积积分值之比G1/G2如果小于0.10,则判定食品没有接受辐照,而且比值越小,接受剂量的可能性就越小;G1/G2如果大于等于0.10,则判定样品辐照过,而且比值越大,接受剂量就越高。The results show that: compared with the unirradiated sample, the data difference of the peak area integral value ratio (G 1 /G 2 ) of the luminescence curve is obvious, and the G 1 /G 2 of the two unirradiated samples are far less than 0.10, while the G 1 /G 2 of the four irradiated samples are all greater than 0.10. With reference to the actual dose of food irradiation at home and abroad, and according to the detection accuracy of the measuring instrument itself, it is set that any food with an irradiation dose above 0.10kGy (including 0.10kGy) is considered as irradiated food; if the food itself Or if one of the excipients received radiation dose less than 0.10kGy, it is considered that the food has not received radiation. Therefore, when the minerals extracted from the sample receive an irradiation dose of 1 kGy, if the ratio G 1 /G 2 of the peak area integral value of the luminescence curve is less than 0.10, it is determined that the food has not received irradiation, and the smaller the ratio, the higher the dose received. The less likely it is; if G 1 /G 2 is greater than or equal to 0.10, it is determined that the sample has been irradiated, and the larger the ratio, the higher the received dose.
未经辐照中辣片的热释光第一、二发光曲线如图2和图3。在150℃到260℃之间的第一、二发光曲线的峰面积积分别为419000(G1)和10048400(G2),G1/G2=0.040;而且二者的曲线形状有比较明显的差异,可以判定此样品没有接受过辐照,与实际情况相符。经辐照的土豆(2)样品的热释光第一、二发光曲线如图4和图5所示。根据试验操作条件,在150℃到260℃之间的第一、二发光曲线的峰面积积分别为1146100(G1)和5696300(G2),G1/G2=0.20;而且二者的曲线形状比较相似,可以判定土豆为辐照过的样品,与实际情况相符。从两组图中比较可知,在样品的第一发光曲线上都有许多“毛刺”,而第二发光曲线上基本保持平滑。毛刺的出现与样品中提取的矿物质的纯净程度有很密切的关系,提取的矿物质含有的杂质(主要是有机物和碳酸盐)越多,毛刺出现的可能性就越大。在第一阶段矿物质在200多度的高温下可以使得杂质大部分灰化,然后辐照一定剂量,获取的第二发光曲线就基本光滑了;但在小于150℃的条件下随着温度逐渐升高会出现一个低温峰,这是样品辐照一定剂量后俘获较浅的电子首先逸出的结果。The thermoluminescence first and second luminescence curves of unirradiated spicy slices are shown in Fig. 2 and Fig. 3 . The peak area products of the first and second luminescence curves between 150°C and 260°C are 419000 (G 1 ) and 10048400 (G 2 ), respectively, G 1 /G 2 =0.040; and the curve shapes of the two are relatively obvious It can be judged that this sample has not been irradiated, which is consistent with the actual situation. The thermoluminescence first and second luminescence curves of the irradiated potato (2) sample are shown in Fig. 4 and Fig. 5 . According to the experimental operating conditions, the peak area products of the first and second luminescence curves between 150°C and 260°C are 1,146,100 (G 1 ) and 5,696,300 (G 2 ), G 1 /G 2 =0.20; The shapes of the curves are relatively similar, and it can be determined that the potatoes are irradiated samples, which is consistent with the actual situation. From the comparison of the two groups of figures, it can be seen that there are many "burrs" on the first luminescence curve of the sample, while the second luminescence curve remains basically smooth. The appearance of burrs is closely related to the purity of the extracted minerals in the sample. The more impurities (mainly organic matter and carbonate) contained in the extracted minerals, the greater the possibility of burrs. In the first stage, minerals can ash most of the impurities at a high temperature of more than 200 degrees, and then irradiate a certain dose, and the obtained second luminescence curve is basically smooth; but under the condition of less than 150 degrees, as the temperature gradually There will be a low-temperature peak when the temperature rises, which is the result that the shallower electrons escape first after the sample is irradiated with a certain dose.
因此,为了证明该检测判据的准确性和有效性,通过对国家规定的允许辐照的6大类食品中,选取了固态和液态食品,以及干、鲜果蔬等85个样品分别用步骤一所述的方法提取矿物质,进行了热释光检测分析,其中45个样品接受实际工艺需要的辐照剂量,结果如图1所示,表明45个辐照样品经热释光分析仪检测后,G1/G2的比值均大于0.1,判别正确率达100%;40个未辐照样品经鉴定后,有38个未辐照样品G1/G2的比值均小于0.1,有2个未辐照样品的G1/G2的比值均等于0.1,判别正确率达95%。最后统计得出一个定性判断依据:即,当G1/G2≥0.10时,判定样品是辐照过的,而且比值越大,接受辐照剂量就越大;而G1/G2<0.10时,判定样品是未辐照的,比值越小,接受辐照的可能性就越小。Therefore, in order to prove the accuracy and effectiveness of the detection criterion, 85 samples of solid and liquid food, as well as dry and fresh fruits and vegetables were selected from the 6 categories of food that are allowed to be irradiated according to the national regulations. The described method extracts mineral matter, has carried out thermoluminescent detection and analysis, and wherein 45 samples accept the irradiation dosage that actual technology needs, and the result is shown in Figure 1, shows that after 45 irradiated samples are detected by thermoluminescence analyzer , the ratios of G 1 /G 2 were all greater than 0.1, and the correct rate of discrimination was 100%; after identification of 40 unirradiated samples, the ratios of G 1 /G 2 of 38 unirradiated samples were all less than 0.1, and 2 The ratios of G 1 /G 2 of the unirradiated samples were all equal to 0.1, and the correct rate of discrimination was 95%. Finally, a qualitative judgment basis is obtained through statistics: that is, when G 1 /G 2 ≥ 0.10, it is determined that the sample has been irradiated, and the larger the ratio, the greater the radiation dose received; while G 1 /G 2 <0.10 When , it is judged that the sample is not irradiated, and the smaller the ratio, the less likely it is to be irradiated.
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| US5606163A (en) * | 1995-01-11 | 1997-02-25 | The United States Of America As Represented By The Secretary Of The Navy | All-optical, rapid readout, fiber-coupled thermoluminescent dosimeter system |
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| JPH11302641A (en) * | 1998-04-17 | 1999-11-02 | Read:Kk | Monoclinic hydroxide phosphor and its production |
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