ordertab() might segfault #168
Description
x = as.integer64(1:10)
x = c(x, x[1:8], x[1:6])
for (ii in 1:100) ordertab(x, order(x), 4)Seems it doesn't segfault every time, but it does so pretty consistently.
{{ message }}
x = as.integer64(1:10)
x = c(x, x[1:8], x[1:6])
for (ii in 1:100) ordertab(x, order(x), 4)Seems it doesn't segfault every time, but it does so pretty consistently.