The bytearray() value set to bytes.partition() and bytes.rpartition() is not converted to a bytes() value, keeping a bytearray() value in a tuple #137217
Description
Bug report
Bug description:
The bytearray() value set to bytes.partition() and bytes.rpartition() is not converted to a bytes() value, keeping a bytearray() value in a tuple as shown below:
v = bytes(b'ABCD')
# ↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓ # ↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓
print(v.partition(bytearray(b'BC'))) # (b'A', bytearray(b'BC'), b'D')
print(v.rpartition(bytearray(b'BC'))) # (b'A', bytearray(b'BC'), b'D')
# ↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑ # ↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑The bytearray() value set to bytes.partition() and bytes.rpartition() should be converted to a bytes() value, not keeping a bytearray() value in a tuple because they are bytes functions and because of readability and consistency as shown below:
v = bytes(b'ABCD')
# ↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓ # ↓↓↓↓↓
print(v.partition(bytearray(b'BC'))) # (b'A', b'BC', b'D')
print(v.rpartition(bytearray(b'BC'))) # (b'A', b'BC', b'D')
# ↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑ # ↑↑↑↑↑In addition, the bytes() value set to bytearray.partition() and bytearray.rpartition() is converted to a bytearray() value, not keeping a bytes() value in a tuple as shown below:
v = bytearray(b'ABCD')
# ↓↓↓↓↓↓↓↓↓↓↓↓ # ↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓
print(v.partition(bytes(b'BC'))) # (bytearray(b'A'), bytearray(b'BC'), bytearray(b'D'))
print(v.rpartition(bytes(b'BC'))) # (bytearray(b'A'), bytearray(b'BC'), bytearray(b'D'))
# ↑↑↑↑↑↑↑↑↑↑↑↑ # ↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑CPython versions tested on:
3.12
Operating systems tested on:
Windows