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Update chinese-remainder-theorem.md
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src/algebra/chinese-remainder-theorem.md

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@@ -154,7 +154,7 @@ $$\left\{\begin{align}
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a & \equiv 2 \pmod{6}
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\end{align}\right.$$
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It is pretty simple to determine is a system has a solution.
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It is pretty simple to determine if a system has a solution.
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And if it has one, we can use the original algorithm to solve a slightly modified system of congruences.
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A single congruence $a \equiv a_i \pmod{m_i}$ is equivalent to the system of congruences $a \equiv a_i \pmod{p_j^{n_j}}$ where $p_1^{n_1} p_2^{n_2}\cdots p_k^{n_k}$ is the prime factorization of $m_i$.

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